Mathematics
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OpenStudy (anonymous):
1/2(6-y)=y?
one half that is.
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OpenStudy (anonymous):
So do you mean\[\frac{1}{2}(6-y)=y\]
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Do you know the distributive property?
OpenStudy (anonymous):
Yes, I was just confused on what you do after you distribute.
OpenStudy (anonymous):
What did you get after you distribute the 1/2?
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OpenStudy (anonymous):
3-1/2y=y
OpenStudy (anonymous):
Can you get the y alone on one side of the = ?
OpenStudy (anonymous):
So, you would subtract y from -1/2y?
OpenStudy (anonymous):
I think you mean subtract y from both sides (leaving 0 on the right). You could do that. What do you get when you do that?
OpenStudy (anonymous):
3-1/2=5/2
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OpenStudy (anonymous):
Where did the y go?
OpenStudy (anonymous):
Never mind, I explained it wrong. Can we start over?
OpenStudy (anonymous):
From 3-1/2y=y
OpenStudy (anonymous):
If you go back to 3-(1/2)y = y, there's a -(1/2)y on the left that wants to be on the right. So try adding (1/2)y to both sides.
OpenStudy (anonymous):
I got the answer. Thank you!
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OpenStudy (anonymous):
Post what you got so I can see.
OpenStudy (anonymous):
2=y
OpenStudy (anonymous):
Yep.
3-(1/2)y = y
3 = (3/2)y
y = 3/(3/2) = 3*(2/3) = 2
OpenStudy (anonymous):
Thank you!
OpenStudy (anonymous):
np
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OpenStudy (anonymous):
OR,
6-y=2y (using cross multiplication, avoids working with fractions)
6=3y
y=6/3=2