Question

how would i solve this problem
-6=(x/2)^3+2

Answer 1

You need to isolate x. To do this you need to start using operations to get x by itself.

Answer 2

how would i get rid of (x/2)^3

Answer 3

Take the cubed root of both sides.

Answer 4

so it would be -2=x/2

Answer 5

convert it to:

x^3=-64

Answer 6

x^3=(-4)^3
x=-4

Answer 7

where did u get the -64 ?

Answer 8

\[(x/2)^{3}=-8\]\[(x ^{3}/-8)=-8\]\[x ^{3}=64\] obtained by multiplying both sides by -8.
x=4 obtained by taking the cube root of both sides.

Answer 9

oops a mistake i see.
\[x ^{3}/8=-8\] now multply by 8
\[x ^{3}=-64\]
x=-4

Answer 10

more better lol

Answer 11

(x/2)^3 is x^3/8 so the cube stays with x

Answer 12

yes

Answer 13

Any questions?

Answer 14

why does the cube stay ?

Answer 15

The exponent "3" applies to everything within the parenthesis both the numerator and the denominator. so both the 2 and the x are cubed.

Answer 16

that would result in x^3/8

Answer 17

\[(2/4)^{3}=8/64=1/8\]

Answer 18

\[(a/b)^{3}=a ^{3}/b ^{3}\]

Answer 19

Do you follow with understanding?