Question

Solve for x: log4x+log4(x+1)=7

Answer 1

this is
\[\log_4(x)+\log_4(x+1)=7\] right?
then
\[\log_4(x(x+1))=7\] so
\[x^2+x=7^4\] yikes

Answer 2

typo should be
\[x^2+x=4^7\] double yikes

Answer 3

if this is really the problem, your job is to solve
\[x^2+x-16384=0\] using the quadratic formula. glad it is you and not me

Answer 4

i don't suppose it might be
\[\log_4(x)+\log_4(x+1)=\log_4(7)\] is it?

Answer 5

actually thats what it is
i forgot to put exponents
thanks for correcting me