Question

p(x)=-2x^2+60x-120

Im not sure how to do this im getting so lost on my homework any help?

Answer 1

what's the question?

Answer 2

Im not really sure where to start I need to find 3 things Whats the largest number of cases that can be sold?

How its possible to loose money?

how many cases should be sold to make a profit?

Im not sure where to start in finding these three options.

Answer 3

\[\text{saifoo}_{100}\] to the rescue

Answer 4

Divide both sides by -2:
x^2-30 x+60 = 0
Subtract 60 from both sides:
x^2-30 x = -60
Add 225 to both sides:
x^2-30 x+225 = 165
Factor the left hand side:
(x-15)^2 = 165
Take the square root of both sides:
sqrt(x-15) = sqrt(165)
Eliminate the absolute value:
x-15 = -sqrt(165) or x-15 = sqrt(165)
Add 15 to both sides:
x = 15-sqrt(165) or x-15 = sqrt(165)
Add 15 to both sides:
x = 15-sqrt(165) or x = 15+sqrt(165)

Answer 5

i don't think it asked for the zeros
just the max
use
\[x=-\frac{b}{2a}=-\frac{60}{2\times -2}=\frac{60}{4}=15\]

Answer 6

hmmm where did the 225 come from?

Answer 7

is the question compelte?

Answer 8

complete*

Answer 9

that's the whole equation in my book unfortunatly i'm taking an online stats class i'm lost and my teacher is no help.

Answer 10

there must be something more a paragraph or something..

Answer 11

Pat Kan owns a factory that manufactures souvenir key chains. Her weekly profit ( in hundreds of dollars) is given by p(x)=-2x^2+60x-120, where x is the number of cases of key chains sold.

Answer 12

Whats the largest number of cases that can be sold? -b/2a

How its possible to loose money? when x generates a P(x) > 0

how many cases should be sold to make a profit? When x generates a P(x) > 0

Answer 13

You can find the exact number of cases through trial and error. Start by graphing the function

Answer 14

Or you can do what Dhashni did

Answer 15

yours seems a bit more simplistic i'm looking at what my teacher has for us and all its doing is making me more lost ... I think i get it im gonna try it thanks for the help to all

Answer 16

And also,

If you want to factor -2x^2-60x-120:

-2(x^2-30x-60)
-2(x^2-30x-30x-60)
-2(x(x-30)-30(x-30)
-2((x-30)(x-30))
-2(x-30)^2

Answer 17

Oh and I made a mistake. For loss, x has to generate a P(x) < 0