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Mathematics 22 Online
OpenStudy (anonymous):

Solve for x: log3^x+log3(x+2)=log3^9

OpenStudy (anonymous):

x(x+2) =9

OpenStudy (anonymous):

x^2+2x-9 =0

OpenStudy (anonymous):

Solve using quadratic formula. Ignore the negative solution.

OpenStudy (anonymous):

\[x= \frac{ -2 +\sqrt{40} }{2}\]

OpenStudy (anonymous):

They mean the bases are 3

OpenStudy (anonymous):

\[x= \frac{-2 +2\sqrt{10} }{2} = -1+\sqrt{10}\]

OpenStudy (anonymous):

hey elecenineer check my question do you know directional direvatives

OpenStudy (anonymous):

The reason why you ignore the negative soln is because log(x) occurs in the original question. You cannot take log of a negative. Thus why I did x= (-b + sqrt{b^2-4ac} ) / 2a I didn't do +- because the - case results in a negative solution

OpenStudy (anonymous):

elecengineer you are right your ans work but thanks to both of your

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