Find exact value if: 0
Now I KNOW I answered this question yesterday AND a few minutes ago.
what a answer?
Do you know the formula for sin(a+b)?
yes, but I not sure I solve it right
Post how you solved it. I'll tell you if it's right, or where you went wrong.
can you show your work?
Can YOU show YOUR work?
\[\sin\frac{4}{9}\cos\frac{1}{4}+\cos\frac{4}{9}\sin\frac{1}{4}\]
x doesn't equal 4/9. sin x = 4/9. Use the sin(a+b) formula to expand sin(x-y)
I know you know how to do it because you did it before.
I don't get it
What's the formula for sin(a+b)?
\[cosx=\sqrt{1-(\frac{4}{9})^2}\]this I folow from the book
That's right, but first you have to expand sin(x-y). To do that you need to know the rule for expanding sin(a+b). What is the rule?
sin(a)cos(b)+cos(a)sin(b)
Correct. Now apply that formula to sin(x-y). You use the rule you just typed, but set a=x and b=-y.
sin(4/9)cos(-1/4) +cos(4/9)sin(-1/4)?
Whoa! Hold on there. Don't start substituting values just yet. Expand sin(x-y) using the sin(a+b) formula you just typed.
Also, x and y aren't 4/9 and 1/4. SIN x = 4/9 and SIN y = 1/4. There's a big difference.
how you solve?
Do what I asked you to do. Expand sin(x-y) using the formula you already posted for expanding sin(a+b). Use a=x and b=-y.
yes I did
You wrote sin(a+b) = sin(a)cos(b) + cos(a)sin(b). Use that formula to expand sin(x-y). Just plug in x for a and -y for b.
Post what you got.
I did post
sin(a+b) = sin(a)cos(b) + cos(a)sin(b). sin(4/9)cos(-1/4) +cos(4/9)sin(-1/4)?
Copy and post it again, because I don't see it. It should be an expression in x and y.
sin(a+b) = sin(a)cos(b) + cos(a)sin(b). sin(4/9)cos(-1/4) +cos(4/9)sin(-1/4)?
Neither of those are an expression in x and y.
Also, you don't know the values of x or y. You only know the values of sin(x) and sin(y).
So you need to find an expression involving sin(x), sin(y), cos(x), and cos(y) so you can plug in the values that you DO know.
That's why I keep asking you to use the sin(a+b) formula to expand sin(x-y). That will yield an expression involving sin(x), sin(y), cos(x), and cos(y).
It getting late I need go sleep,I will work on it, I f I don't get I will post again tomorrow,ty
sin(x - y) =sinx*cosy - cosx*siny
\[sin^2\theta + cos^2\theta = 1 \]
You can get cos values with the above identity
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