Question

a great proof of 1=2

Answer 1

Let ... a = b

Multiply both sides by 'a'


Add a2 to both sides



Subtract 2ab from both sides



cancel the common factor from both sides
Hence 2=1

Answer 2

Think and tell what is done wrong here ?

Answer 3

Let a=b
multiply both sides by 'a'

a2=ab

add a2 to both sides

a2+a2=a2+ab

2a2=a2+ab

Subtract 2ab from both sides

2a2-2ab=a2+ab-2ab

2a2-2ab=a2-ab

2(a2-ab)=1(a2-ab)

therefore 1=2...........

Answer 4

Let a = b
multiply both sides by a
a^2 = a*b
subtract b^2 from both sides
a^2-b^2 = a*b-b^2
apply the distributive law to both sides
(a+b)(a-b) = b(a-b)
divide both sides by (a-b)
(a+b) = b
substitute all a's for b's (remember, if a = b you can do this)/
a+a = a
regroup the two a's in the left side, and rename it 2a
2a = a
divide both sides by a
2 = 1

Answer 5

2(a2-ab)=1(a2-ab)
how can u cancel while a2-ab=0

Answer 6

0/0 is undefined

Answer 7

wrong step

Answer 8

any more answers !

Answer 9

you can not devide a number by zero.
:))

Answer 10

ok any more ?

Answer 11

Sajan And zakaullah is right

Answer 12

Let f(x) = x+1 and g(x) = x
f(1) = 2, g(1) = 1
f'(x) = 1, g'(x) = 1
f'(x) = g'(x)
f(x) = g(x)
f(1) = g(1)
2 = 1