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A=^3√36V² rearrange so v is subject
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\[A=\sqrt[3]{36v^2}\]THat?
yeh, sorry
take cube on both sides. \[A^3 = 36 v^2\]
Multiply 36 on both sides, \[\frac{A^3}{36}=v^2\]
Now, take a square root on both sides to cancel the v^2 So, the final answer will be: \[v=\sqrt{\frac{A^3}{36}}\]
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i got that but brackets around \[A^3/36\] instead, thanks
Oh, you welcome.
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