Question

Suppose
f(π/3) = 2 and f '(π/3) = −3,
and let
g(x) = f(x) sin x
and
h(x) = (cos x)/f(x).
Find the following

Answer 1

Find what?

Answer 2

i bet it is
\[g'(\frac{\pi}{3})\]

Answer 3

yes lol

Answer 4

More proof that satellite needs to retire

Answer 5

by the product rule
\[g'(x)=f'(x)\sin(x)+f(x)\cos(x)\] now plug in
\[\frac{\pi}{3}\] so get your answer

Answer 6

When you know the question before it is even asked, it's time to retire.

Answer 7

what else could it be??

Answer 8

i did all of that and i keep getting a wrong answer

Answer 9

same for next one but use the quotient rule.
really? lets try it

Answer 10

\[g'(x)=f'(x)\sin(x)+f(x)\cos(x)\]
\[g'(\frac{\pi}{3})=f'(\frac{\pi}{3})\sin(\frac{\pi}{3})+f(\frac{\pi}{3})\cos(\frac{\pi}{3})\]
\[g'(x)=-3\times \frac{\sqrt{3}}{2}+2\times \frac{1}{2}\] is as start

Answer 11

we get
\[1-\frac{3\sqrt{3}}{2}\] or if you prefer
\[\frac{2-3\sqrt{3}}{2}\]

Answer 12

i did that too : )))
but its telling me its a wrong answer lol

Answer 13

and got the same answer as you...

Answer 14

then be happy with your answer and tell "it" to @#$% off

Answer 15

maybe a syntax error? i take it this is on line homework

Answer 16

yes its a webassign crap and i am so mad....
thank you for your help

Answer 17

i am familiar with web assign. best bet is to contact your teacher and say "this is what i think is right"

Answer 18

okay thank a lot : )))

Answer 19

yw