so if in an equation has 2 unknown values is it still unfactorable?
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OpenStudy (anonymous):
you can't solve a single equation with more than one variable (unknown), but that has nothing to do with factoring. you may factor an expression with more than one variable
OpenStudy (amistre64):
x^2 - y^2 can be factored
OpenStudy (anonymous):
for example: X^2+2ax+a^2
OpenStudy (anonymous):
yes, that is factorable as (x+a)^2
OpenStudy (anonymous):
let me try first and if I can't factor it I'll come back. :D
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OpenStudy (anonymous):
amistre's example also is factorble into (x-y)(x+y)
OpenStudy (anonymous):
but you can't SOLVE 2x+5y=10, for example
OpenStudy (anonymous):
ok
can u tell me how did you factor this equation??thanks
OpenStudy (anonymous):
amistre's example is a difference of two squares; it factors according to a formula\[a^2-b^2=(a-b)(a+b)\]you can check this by multiplying the RHS (FOIL) and you will get the LHS.
OpenStudy (anonymous):
your example is a perfect square trinomial\[(p+q)^2=p^2+2pq+q^2\]
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