Question

a block of mass 10.0 kg slides without friction at a speed of 8.0 m/s on a horizontal table surface until it strikes and sticks to a mass of 4.0 kg attached to a horizontal spring (with a spring constant k = 4000 N/m), which in turn is attached to the wall. How far is the spring compressed before the mass comes to rest

Answer 1

Sorry, No idea. LOL.

Answer 2

sigh...

Answer 3

Find the kinetic energy of the block... E=1/2mv^2 this is turned into potential energy in the spring.... you can find he compression distance from that.

Answer 4

so if E is 192

Answer 5

that's using 1/2 (10.0 - 4.0) (8.0)^2

Answer 6

how do i find compression distance?

Answer 7

E=1/2kx^2

Answer 8

192=1/2Kx^2

Answer 9

so 192 = 1/2 (4000) and solve for x^2?

Answer 10

yes

Answer 11

okay...i get .3098386677 which isn't an option

Answer 12

you did consider momentum transfer though right?

Answer 13

E=1/2mv^2 is the total energy of the blocks.... there is completely elastic collision that happens...

Answer 14

find the final speed of the 2 blocks by: m1v1=(m1+m2)V

Answer 15

after you find that THEN use the E=1/2mV^2 equation

Answer 16

(m1+m2)V is 112

Answer 17

then i plug that into E = 1/2 (112)(8.0)^2

Answer 18

i get 3584

Answer 19

no the V changes..... find V in the momentum transfer equation you know the rest