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Evaluate lim u-> infinity (tan^-1 u)
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that would be \[\frac{\pi}{2}\]
\[\lim_{u \rightarrow \infty}( \tan ^{-1}u)\]
can u plz show some work
im not sure how 2 approach it
i am not sure what "work" there is. range of arctangent is \[(-\frac{\pi}{2},\frac{\pi}{2})\] because that is what you restrict the domain of tangent to make it one to one
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as \[\lim_{x\rightarrow \frac{\pi}{2}^-} \tan(x)=\infty\] then you get your limit
so teh answer is pi/2 to the left side
|dw:1317604084868:dw|
your best bet is to look at the graph (not my crappy picture) of \[y=\tan(x)\] and of \[y=\tan^{-1}(x)\] and the limit will be clear
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i see. so how come u wrote pi/2 from te hleft side ...= infinity
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