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Mathematics 23 Online
OpenStudy (anonymous):

find equation of tangent line to the curve at given point. y= x^4 +5x^2 -x at the point (1, 5)

OpenStudy (anonymous):

you would find derivative first, becuase that is = to slope right?

OpenStudy (anonymous):

take the derivative, replace x by 1 to get the slope, then use the point-slope formula

OpenStudy (anonymous):

ok...i did that, would it be y= 44x - 39 ?

OpenStudy (anonymous):

where did the "44" come from?

OpenStudy (anonymous):

crap i see what i did...for some reason i used 10 instead of 12 for the derivative of second term

OpenStudy (anonymous):

nope thats not it either haha...

OpenStudy (anonymous):

\[y'=4x^3+10x-1\] so if x = 1 the slope would be 13

OpenStudy (anonymous):

how the heck did i get a 44? hahah

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

yw

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