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find equation of tangent line to the curve at given point. y= x^4 +5x^2 -x at the point (1, 5)
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you would find derivative first, becuase that is = to slope right?
take the derivative, replace x by 1 to get the slope, then use the point-slope formula
ok...i did that, would it be y= 44x - 39 ?
where did the "44" come from?
crap i see what i did...for some reason i used 10 instead of 12 for the derivative of second term
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nope thats not it either haha...
\[y'=4x^3+10x-1\] so if x = 1 the slope would be 13
how the heck did i get a 44? hahah
thanks
yw
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