the circle x^2 + y^2 = 49 consists of four one-to-one functions f1, f2, f3, f4.
(1) find a formula for the function f1 and its domain.
(2) find the inverse of function f1 and write it as y= f^(-1)x

Question

the circle x^2 + y^2 = 49 consists of four one-to-one functions f1, f2, f3, f4. 
(1) find a formula for the function f1 and its domain. 
(2) find the inverse of function f1 and write it as y= f^(-1)x

anonymous · Answer

you could say 
$$f_1(x)=\sqrt{1-x^2}\text{ for } 0\leq x<1$$ for example

anonymous · Answer

why is that?

anonymous · Answer

you want a one to one function
so you have to break it into 4 parts
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anonymous · Answer

there are 4 one to one functions that together give the circle.

anonymous · Answer

if you label them 
$$f_1,f_2,f_3,f_4$$ respectively, they will give you the whole thing.  you cut them off by restricting the domain

anonymous · Answer

you can see that 
$$f_1$$ is for x from 0 to 1

anonymous · Answer

wouldnt it be f(x) = x + 7 because you just solve for y and it's positive in the first quadrant?

anonymous · Answer

the answer you gave me is apparently wrong

anonymous · Answer

ok let me do it correctly.  the radius is 7, and so it would be 
$$f_1(x)=\sqrt{49-x^2} \text{ for } 0\leq x < 7$$

anonymous · Answer

i forgot the radius was 7 and not 1, sorry

anonymous · Answer

thats alright and thank you

anonymous · Answer

yw

anonymous · Answer

to find the inverse do i just solve for x from that equation?