If the tangent line to the graph of the funtion f(x) at the point (1,7) passes through the point (-2,2), then what is f'(x)?
find the slope of that line i assume it means what is \[f'(1)\]
you cannot know \[f'(x)\] unless you know \[f(x)\] but \[f'(1)\] will be your slope
so is it 5/3?
yes again that is if you were asked for \[f'(1)\]
oh shoot, i thought i put f'(1). hahaha. thanks satellite73!
i got the answer from just getting the slope of the two points. i need to show work though. can you help me?
show the work for finding the slope?
you can do it with your eyeballs, over 3 up 5 slope is \[\frac{5}{3}\] like you already said. that is all the work. however you computed the slope, write that down and you are done
something like \[f'(1)=\frac{7-2}{1+2}=\frac{5}{3}\]
hahaha, i just expected the question to have lots of work to be shown. thanks again!
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