Question

Y=2|x|+k
Y=2(x+1)^2-4
All values of k for which y=2|x|+k is a secant to Y=2(x+1)^2-4

Answer 1

I'm sure myininaya can help you. James J was here all day. You missed him.

Answer 2

What course are you taking?

Answer 3

grade12 math adv function

Answer 4

So this isn't very hard

Answer 5

uh i think i arrived at solution but im not sure if its right........

Answer 6

Oh really

Answer 7

Of course we would start out by graphing it, no?

Answer 8

well there are two slopes in this case -2x and 2x right?

Answer 9

both have limited value

Answer 10

Should be two slopes and two values of k for each

Answer 11

yh but x>0 poses no answer i think

Answer 12

so only for x<0 i think there are answers

Answer 13

I responded too fast. I was thinking about x, not k

Answer 14

lol i figured as much

Answer 15

Satellite is here now. Maybe he can help you out

Answer 16

well not really sorry. i do not know what "secant to ... " means

Answer 17

Are you implying that "secant to" makes no sense or you just honestly don't know

Answer 18

no i really don't know