Y=2|x|+k
Y=2(x+1)^2-4
All values of k for which y=2|x|+k is a secant to Y=2(x+1)^2-4

Question

hero · Answer

I'm sure myininaya can help you. James J was here all day. You missed him.

hero · Answer

What course are you taking?

anonymous · Answer

grade12 math adv function

hero · Answer

So this isn't very hard

anonymous · Answer

uh i think i arrived at solution but im not sure if its right........

hero · Answer

Oh really

hero · Answer

Of course we would start out by graphing it, no?

anonymous · Answer

well there are two slopes in this case -2x and 2x right?

anonymous · Answer

both have limited value

hero · Answer

Should be two slopes and two values of k for each

anonymous · Answer

yh but x>0 poses no answer i think

anonymous · Answer

so only for x<0 i think there are answers

hero · Answer

I responded too fast. I was thinking about x, not k

anonymous · Answer

lol i figured as much

hero · Answer

Satellite is here now. Maybe he can help you out

anonymous · Answer

well not really sorry. i do not know what "secant to ... " means

hero · Answer

Are you implying that "secant to" makes no sense or you just honestly don't know

anonymous · Answer

no i really don't know

anonymous · Answer

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