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Is .63 the eccentricity of the ellipse x^2/49 + y^2/81 =1
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yes
to two decimal places
Thank you. I'm having a hard time figuring this out. I know the formula is e = c^2/a but I don't get this answer. I'm guessing. Any suggestions?
\[\sqrt{1-(\frac{9}{7})^2}\]
or \[\sqrt{\frac{a^2-b^2}{a^2}}\]
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by which i mean \[\sqrt{\frac{a^2-b^2}{a^2}}=\sqrt{1-(\frac{b}{a})^2}\] so you can use whatever you find easiest
sorry i had your backwards. it should have been \[\sqrt{1-(\frac{7}{9})^2}\]
the thing inside the radical must be positive, so the bigger number goes irst or in the denominator
My lesson says the formulat is y = a^2/c so I get 81/4 = 20.25. Where am I going wrong?
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