Question

an altitude h of a triangle is increased by a length m.how much must be taken from the corresponding base b so that the area of the new triangle is half of the origignal triangle

Answer 1

\[\frac{1}{2}b*h = 2*\frac{1}{2}(b-x)*(h+m)\]

Answer 2

can u tell me the answer only please

Answer 3

\[x = \frac{-1}{2}\frac{b*h}{h+m} - b\]

Answer 4

Or maybe I meant:
\[x = \frac{-1}{2}\frac{b*h}{h+m} + b\]

Answer 5

answer? + b or - b

Answer 6

I yhink the answer is :
\[\frac{b(2m+h)}{2(h+m)}\]