solve the integration :
$$\int\limits_{\int\limits_{0}^{1}((x^2 + x^3)dx)/2}^{ \int\limits_{+\infty}^{-\infty}(x^2 /3)dx}\sqrt{tanx}dx$$

Question

solve the integration : 
$$\int\limits_{\int\limits_{0}^{1}((x^2 + x^3)dx)/2}^{ \int\limits_{+\infty}^{-\infty}(x^2 /3)dx}\sqrt{tanx}dx$$

across · Answer

haha, wow.

anonymous · Answer

I like fantasy, anormal questions like this :) really looks like a challenge yea? :D

across · Answer

i don't know, but whoever solves that will never again have a problem with definite integrals ^^

anonymous · Answer

i wud rather get zero than to waste my time ,in an exam or test, since the an intergratiom bound cannot be an intergration.not unless its double intergrals.

anonymous · Answer

down limit is easy, just do integration by parts, but upper limit.. the infinities, i have no idea :)

anonymous · Answer

posible answere can ne pi/4 .since arctan(pi/4)=infinity.

jamesj · Answer

This integral doesn't exist, as the lower limit is finite, the upper limit is -infinity

and hence the integrand, 

sqrt(tan x) 

doesn't even exist half the time over that domain.

angela210793 · Answer

Anxhela SHOCKED!!!!!! :P:P:P |dw:1317715704508:dw|