Question

integral of xln(x^2+1) dx from (0,1)

Answer 1

where did the answer go?

Answer 2

i made a mistake.

Answer 3

wait i will give u one .

Answer 4

let u=x^2+1

Answer 5

k

Answer 6

the antiderivative of ln(x) is x ln(x)-x+C
since the derivative of (x ln(x)-x)'=ln(x)+1-1=ln(x)

Answer 7

in my answer ad 1+1/4

Answer 8

so
the antiderivative of ln(u) is u ln(u)-u+C
since the derivative of (u ln(u)-u)'=ln(u)+u-u=ln(u)

Answer 9

so I did that all wrong?

Answer 10

yes its wrong!

Answer 11

I ended up with -1/4

Answer 12

or if u think i ur not find the derevative of 1/x. and c if u can.

Answer 13

it would be -x^-2

Answer 14

what?
i think you are getting confused
\[\int\limits_{}^{}\frac{1}{u} dx=\ln|u|+C\]
\[\int\limits_{}^{}\ln(u) du=u \ln(u)-u+C\]
\[(\frac{1}{u})'=\frac{-1}{u^2}\]

Answer 15

okay so is -1/4 the wrong answer?

Answer 16

yeh ur right im just tired i need to go to sleep.forgot that ,thanks for the alert.

Answer 17

it happens to all of us
we all get tired

Answer 18

i was writing physics , but i promise 2moro morning i will be 5n.