Question

if z=a-ai and (2z+3)^2012=(z+5)^2012
find a

Answer 1

i think a = -2

Answer 2

thank you

Answer 3

hold on i am changed my mind

Answer 4

\[2z+3=(2a+3)-2ai\]
\[z+5=(a+5)-ai\]
when you raise these numbers two that huge power the absolute value is raised, and the angle is multiplied, so the absolute values must have been the same to begin with, in other words
\[(2a+3)^2+4a^2=(a+5)^2+a^2\] and solve that quadratic. you do not get -2, i made a mistake

Answer 5

thank you soooooo much :)