Question

The absolute value of [x^2 + x] = 12

Answer 1

(x^2+x)=12 and (x^2+x)=-12
x^2+x-12=0 and x^2+x+12=0
(x+4)(x-3)=0 and \[x=(-b \pm \sqrt{b^2-4ac})/2a\]
So x=-4, 3 and the roots of x^2+x=-12 are imaginary
So x= -4, 3