Question

Solve 2x^2+5x-3=0

Answer 1

\[2x^2 + 5x - 3 = 0\]
\[2x^2 + 5x + \frac{25}{16} = 3 + \frac{25}{16}\]
\[(\sqrt{2}x + \frac{5}{4})^2 = 3 + \frac{25}{16}\]
\[\sqrt{2}x + \frac{5}{4} = \sqrt{3 + \frac{25}{16}}\ \ \ \ \ or \ \ \ \ \ \sqrt{2}x + \frac{5}{4} = -\sqrt{3 + \frac{25}{16}}\]

Answer 2

Thank you!

Answer 3

factor: (2x+1)*(x-3)=0
x=-1/2
x=3