how do i solve this? find the distance traveled in 15 seconds by an object moving with a velocity of v(t) = 20 +7cos(t) feet per second
Velocity is the derivative (rate of change) of position, so position is the integral of velocity. Integrate the function over the range 0 to 15s.
can u show me how? is it just v(t)=20+7cos15?
That will only give you the velocity at time t. You need to integrate that expression to find position. Do you know how to do an integral?
no i dont
Do you understand this: \[\int\limits\limits_{0}^{15}v(t)dt = \int\limits\limits_{0}^{15}(20+7\cos(t))dt=\int\limits_{0}^{15}20dt + 7\int\limits_{0}^{15}\cos(t)dt\]
no i have never seen that before what does dt stand for? distance x time?
dt means you need to do the integral over the variable t. I'm surprised they're asking you to do a problem with integrals if you don't know how to do integrals. Integral calculus is a much too difficult subject to teach in an openstudy post.
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