Question

Find the area of the largest isosceles triangle that can be inscribed in a circle of radius 6 inches.

Answer 1

if the radius is 6 inches than the height of this triangle is 9 inches because the radius is 2/3 from this height so than h=(6*3)/2=9

Answer 2

area equal base multiply height divide 2 = (b*9)/2

Answer 3

all angles are 60 degrees.
2/3h=r
2/3h=6
h=9

then since you have a right triangle you can have the base as (9tan30)=sqrtof3 over 3

then solve for area of triangle 1/2 bh = 1/2(sqrt3 over 3)(9) but this is just 1 triangle so you need to multiply it by 2 so just bh = sqrt of 3 over 3 * 9

Answer 4

approximately 5.2 squared inches