Question

Integration question.

Answer 1

Integration! ...

Answer 2

Hey

Answer 3

Hey, what's the question?

Answer 4

\[\int\limits_{nothing}^{nothing} (5) / \sqrt(5-x^2)\]

Answer 5

I tried this using inverse trignometric functions

Answer 6

\[\int \frac{5}{\sqrt{5-x^2}}dx\]

Answer 7

Yes that is correct

Answer 8

\[5 \int \frac{1}{\sqrt{5\left(1 - (\frac{x}{\sqrt 5})^2)\right)}}dx\]

Answer 9

\[\frac{5}{\sqrt 5 } \frac{1}{\sqrt{1 - \left(\frac{x}{\sqrt{5}}\right) ^2}}\]

Answer 10

Yes that is correct

Answer 11

I have a question

Answer 12

Yes that is correct

Answer 13

You see on the previous step

Answer 14

\[\int \frac{5}{\sqrt 5 } \frac{1}{\sqrt{1 - \left(\frac{x}{\sqrt{5}}\right) ^2}}dx\]Now use \[\int \frac{1}{\sqrt{1-x^2}}dx = \sin^{-1}x\]

Answer 15

Yes that is correct

Answer 16

How you took sqrt(5) out, doesn't it come 25?

Answer 17

Yes that is correct

Answer 18

become

Answer 19

\[\sqrt{ 5}*\sqrt { 1 - \frac{x^2}{5}}= \sqrt{5(1 - \frac{x^2}{5})}\]

Answer 20

Yes that is correct

Answer 21

Excellent

Answer 22

Yes that is correct

Answer 23

Thanks for your help. =)

Answer 24

:)

Answer 25

Dont you need a ln|x| in that general form? (from cancelling the radicals)

Answer 26

nvm, im being dumb

Answer 27

Yes that is correct

Answer 28

Lol

Answer 29

Yes that is correct

Answer 30

Hey, how do i close this answer?

Answer 31

\[\int \frac{5}{\sqrt 5 } \frac{1}{\sqrt{1 - \left(\frac{x}{\sqrt{5}}\right) ^2}}dx\]
\[ \sqrt{5} * \sin^{-1} \frac{x}{\sqrt{5}}*\frac{1}{\sqrt{5}} +C\]
\[\sin ^{-1} \frac{x}{\sqrt{5}} + C\]

Answer 32

Yes that is correct

Answer 33

I got this as the final answer:

Answer 34

Yes that is correct

Answer 35

\[\int\limits5\sin^{-1} (x/\sqrt5)+c\]