Question

What is the equation, in standard form, of a vertical hyperbola with asymptotes at y + 8 = ±(x – 8)?

Answer 1

you see that the slope of the asymps is 1 right?

Answer 2

which means that a = 1 and b = 1 in the conventional hyperB equation

Answer 3

\[\frac{x}{1}^2-\frac{y}{1}^2=1\]
now the issue is the center; so where do these asymps cross at?

Answer 4

y = +-x -+ 8- 8

y = +-x -16, +0

one has a yint of -16; the other at 0; so it looke to cross at y=-8

Answer 5

Sorry, went to get coffee. I have( y-8)^2/81 - (x+8)^2/4 = 1

Answer 6

where does 81 and 4 come from?

Answer 7

Sorry, I left off something form the original equation, ugghh. It is
y+or - 2/9(x-8). So 81 comes from squaring the 9 and 4 comes from squaring the two

Answer 8

ok .... then i will need to know what the whole question is. Since i am trying to answer the post itself :)

Answer 9

asymps are: \(y=\pm\frac{2}{9}(x-8)\) right?

Answer 10

What is the equation, in standard form, of a vertical hyperbola with asymptotes at y+8= plus/minus 2/9 (x-8)

Answer 11

well, the point they share in common is: (8,-8) right?

Answer 12

(x-8)^2 (y+8)^2
------- () ------- = 1
a^2 b^2

if we open left to right along the x axis:

(x-8)^2 (y+8)^2
------- (-) ------- = 1
16 81

if we open up and down along the y axis:


(y+8)^2 (x-8)^2
------- (-) ------- = 1
16 81

Answer 13

Ok. I had x as the leading term in the equation,but my choices only give y as a choice. Is that because it is a vertical hyperbole?

Answer 14

Where did the 16 comes from? I though you would square the 2 and get 4

Answer 15

.... yeah, i put 2 thoughts toghter; 2^2 = 4; but since its 4 ... i then requred it in my head

Answer 16

resquared .. lol

Answer 17

So you think the equation with 4 instead of 16 is correct?

Answer 18

no, 2^2 = 4. 9^2 = 81

go with 4 and 81

Answer 19

i did it right in the wolfram ....

Answer 20

What is the worlfram, ha

Answer 21

ummm nothing :) since i messed it up in there as well. go with the 4 and 81

Answer 22

this is the wolfram:

http://www.wolframalpha.com/input/?i=plot+%28%28x-8%29%2F2%29^2+-+%28%28y%2B8%29%2F9%29^2+%3D+1%2C+%28%28y%2B8%29%2F2%29^2+-+%28%28x-8%29%2F9%29^2+%3D+1

Answer 23

Is this a graphing program

Answer 24

its a pretty neat graphing and other stuff engine yes

Answer 25

Great! Is is free? I'm going to post another question if you want to help :)

Answer 26

..... yes, its free