Ask
your own question, for FREE!
Mathematics
8 Online
limit x-> 5 sin(x^2-25) / (x-5)
Still Need Help?
Join the QuestionCove community and study together with friends!
that's equal to lim x => 5 sin(x-5)/(x-5) times x+ 5 sin(x-5)/(x-5) = 1 according to many theorems so.. 1(x+5) = x+5 substitute 5.. 5+5 =10
10
thanks alot.
the above solution of lgbasa. is wrong
because you can't write sin(a*b)=(sina)*b
Still Need Help?
Join the QuestionCove community and study together with friends!
so, what's the correct answer ?
it's sin[(x+5)(x-5)]/x-5..you can't apply double angle theorems or whatever theorems there so i think my solution is valid
\[\sin(x^2-25)/(x-5)=(x+5)*\sin(x^2-25)/((x-5)(x+5))=(x+5)*\sin(x^2-25)/(x^2-25)\]\[x->5 => x^2->25\]\[\lim_{x^2 \rightarrow 25}\sin(x^2-25)/(x^2-25)=1\]so (5+5)*1=10
check this out
that's the correct answer dipankarstudy ?
Still Need Help?
Join the QuestionCove community and study together with friends!
yes i think so...you can consult others..but definitely you can't do the first one
ok, thnx
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
VERNEISH:
Two objects are moving along separate linear paths where each path is described by position, d, and time, t.
Maci:
what are the best stock apps for people who want to start investing?
Twaylor:
genuienly how do i get better self control i keep watcing youtube and theres this
IzzyCookie:
|dw:1792074056138:dw| Uhm, I don't know where to ask this, but I'm in college welding at my community college, and I need help learning vertical welding for
thehearken:
not sure if this is considered spam, im sorry if it is, but does anyone have tips
7 minutes ago
1 Reply
0 Medals
4 days ago
3 Replies
2 Medals
1 week ago
3 Replies
0 Medals
2 days ago
9 Replies
1 Medal
1 week ago
2 Replies
1 Medal