Question

completing the square
x^2 +6x -3 =0

Answer 1

(x+3)^2 - 9 -3 = 0
(x+3)^2 = 12
x+3 = +- sqrt12
x= - 3 + sqrt12 or
-3 - sqrt12

Answer 2

-3 + 3.464 or -3 - 3.464
= 0.464 or -6.464

Answer 3

\[\large{(x+\frac{6}{2})^2-(\frac{6}{2})^2-3=0}\]\[\large{(x+3)^2-(3)^2-3=0}\]\[\large{(x+3)^2-9-3=0}\]\[\large{(x+3)^2=12}\]\[\large{x+3= \pm \sqrt{12}}\]
\[\large{x=\sqrt{12}-3=2\sqrt3-3}\]\[\large{x=-\sqrt{12}-3}=-2\sqrt3-3\]