how do I evaluate: lim x-0 (sin^2(x))/(1-cosx)??

Question

how do I evaluate: lim x->0   (sin^2(x))/(1-cosx)??

anonymous · Answer

use lehopitals rule difrentiat top and botom twice then plug in limit

anonymous · Answer

LOL
omg i cant believe

anonymous · Answer

no need for that

anonymous · Answer

i deleted it by accident :(

 but :

lhosiptal as i said

2sinxcosx / sinx 

2cosx 
plug x = 0

2

anonymous · Answer

$$\frac{(1-\cos(x))(1+\cos(x))}{1-\cos(x)}=1+\cos(x)$$

anonymous · Answer

haha i got it before you deleted it. I kinda understand what you are all saying? but im still a little confused and have more evaluations to do...

anonymous · Answer

replace x by 0, get 2 right away

myininaya · Answer

nice eye satellite

anonymous · Answer

look at the way i  solved it now .. you dont really need to do it twice as i did before

anonymous · Answer

thnx

anonymous · Answer

anyone know a good site for trigonometric identities? thats what gets me

anonymous · Answer

paul's notes is alway good but if you need one on the fly just google it

anonymous · Answer

could you possibly help me with another? i think i may have gotten the first step but i am not sure

anonymous · Answer

sure post away