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evaluate limit->0 1-secx / 1-cosx?
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can i start with 1-1/cosx / 1-cosx?
yes that would be a good idea
\[\frac{1-\frac{1}{\cos(x)}}{1-\cos(x)} \cdot \frac{\cos(x)}{\cos(x)} =\frac{\cos(x)-1}{\cos(x)(1-\cos(x))}\]
what do you think is next
but then i dont know what to do next
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cos(x)-1 is the opposite of 1-cos(x) right?
\[\frac{\cos(x)-1}{\cos(x)(-1)(\cos(x)-1)}\]
yes?
so recall a/a=1 assuming a does not =0
nice okay i got it = -1!!
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ok great
yes that it is!
ok im probably going to post again soon if i get stuck with more of these hehe..
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