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Mathematics 23 Online
OpenStudy (anonymous):

Derivative of 3x-1

OpenStudy (lgbasallote):

3

OpenStudy (anonymous):

w.r.t x , 3 w.r.t any other var ,0

OpenStudy (anonymous):

Could you elaborate on how you found it?

OpenStudy (amistre64):

with something this basic; i think youll have to tell us where youre getting confused at

OpenStudy (anonymous):

Why's the answer simply the coefficient of x? And also what is w.r.t.?

OpenStudy (amistre64):

a straight line, which is what this equation is; change with respect to its slope .....

OpenStudy (lgbasallote):

definiton of derivatives: lim h -> 0 [3(x+h) + 1 - (3x+1)/ h] (3x + 3h + 1 - 3x - 1)/h 3h/h =3

OpenStudy (amistre64):

the instantaneous rate of change of a linear equation IS its slope

OpenStudy (anonymous):

You can also think of the derivative of the function as the function describing slopes of lines tangent to the original function. If our original function is a straight like, all lines tangent to that like ARE that line. At EVERY point. thus out derivative HAS to be a constant. Not sure if that helps, just something to think about.

OpenStudy (anonymous):

"If our original function is a straight like, all lines tangent to that like ARE that line." if our original function is a straight line*, all lines tangent to that line* ARE that line. Also remember that we are describing the slopes here, not the actual lines. It just so happens (in the linearity of our problem) that the slope of our function is the slope of the tangent function/derivative at every point.

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