Question

Derivative of 5/(2x)^3 +2cosx. Step by step please

Answer 1

second term you do by knowing that the derivative of
\[\cos(x)\] is
\[-\sin(x)\] so the second part will be
\[-2\sin(x)\]

Answer 2

first part we can do by the "power rule" after rewriting
\[\frac{5}{(2x)^3}=\frac{5}{8x^3}=\frac{5}{8}x^{-3}\]
the derivative will then be
\[-3\times \frac{5}{8}x^{-4}=\frac{-15}{8x^4}\]

Answer 3

Thanks a ton

Answer 4

yw