Question

find an equation of the tangent line to the graph of f at the given point. f(x)=square root of (x-1)....with points (5,2)

Answer 1

\[y-y_1=f'(x_1)(x-x_1)\]

Answer 2

what is that?

Answer 3

the equation of the line tangent to f(x) at the point \[(x_1,y_1)\]

Answer 4

zarkon!

Answer 5

yo!

Answer 6

i think i did something
take a look at this when you are done :)
http://openstudy.com/groups/mathematics/updates/4e8bae890b8b543d41faa262#/groups/mathematics/updates/4e8bb0ac0b8b543d41fad5b4

Answer 7

i mean if you want to take a look at it

Answer 8

lol

Answer 9

you don't have to
no one is gonna make you

Answer 10

can you show steps cause im confused

Answer 11

f'(x) = 1/2sqrt(x-1)
m = 1/4

Tangent:
y-y1 = m(x-x1)
y-2 = 1/4(x-5)
4y - 8 = x -5
T: x-4y +3 = 0

Answer 12

how did you get the derivative?