find an equation of the tangent line to the graph of f at the given point. f(x)=square root of (x-1)....with points (5,2)

Question

zarkon · Answer

$$y-y_1=f'(x_1)(x-x_1)$$

anonymous · Answer

what is that?

zarkon · Answer

the equation of the line tangent to f(x) at the point $$(x_1,y_1)$$

myininaya · Answer

zarkon!

zarkon · Answer

yo!

myininaya · Answer

myininaya · Answer

i mean if you want to take a look at it

zarkon · Answer

lol

myininaya · Answer

you don't have to
no one is gonna make you

anonymous · Answer

can you show steps cause im confused

mimi_x3 · Answer

f'(x) = 1/2sqrt(x-1) 
m = 1/4 

Tangent: 
y-y1 = m(x-x1)
y-2 = 1/4(x-5)
4y - 8 = x -5
T: x-4y +3 = 0

anonymous · Answer

how did you get the derivative?

mimi_x3 · Answer

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