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Mathematics 20 Online
OpenStudy (anonymous):

Can anyone show me whats up with this number?

OpenStudy (anonymous):

\[i^-55\]

OpenStudy (anonymous):

thats supose to be raised to the -55

OpenStudy (anonymous):

is it \[i^{-55}\]?

OpenStudy (anonymous):

yea sorry i messed up in the equation maker

OpenStudy (anonymous):

so that means \[\frac{1}{i^{55}}\]right?

OpenStudy (anonymous):

Yes but i think i'm supose to get it to equal 1 somehow

OpenStudy (anonymous):

and \[i^{55}\] is easy enough to compute because it goes \[i^0=1,i^1=i,i^2=-1,i^3=-i, i^4=1,...\]

OpenStudy (anonymous):

so i^-55=i?

OpenStudy (anonymous):

so just take the whole number remainder when you divide 55 by 4, and see what you get. it is 3, since 4 goes in to 52 evenly therefore \[i^{55}=i^3=-i\]

OpenStudy (anonymous):

and so \[\frac{1}{i^{55}}=\frac{1}{-i}=\frac{1}{-i}\times \frac{i}{i}=\frac{i}{1}=i\]

OpenStudy (anonymous):

probably a snappier way to do it, but yes it is i

OpenStudy (anonymous):

but it is not 1, that is for sure

OpenStudy (anonymous):

Ok so it's kinda like raising a negitive number to a power if the power is even the number is even, but instead if the power is odd it equals i or if it's even it equals 1?

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