How do you find the derivative of x^2 + y^2?
with respect to which variable?
like for economics we were given U(x,y) = x^2 + y^2 and were asked to find the margin utility with respect to x and y and we have to find partial derivatives but I don't know how to do it... :(
does that make sense at all??
yes, im trying to remember how to do those partial derivatives in general terms, lol they didnt give you any specific points did they?
nope, all it says is U(x,y) = x^2 + y^2
like i have the answer, but i don't know how they got it... they said MUx = 2x and MUy = 2y
am i just over-thinking the question? lol
treat y as constant and differentiate then in second x as constant and then differentiate
Oh, okay, thats what I was going to say at first. I thought you were asking for something else. basically, you take the derivative with respect to each variable separately. so d/dx( x^2+y^2) the first goes to 2x (drop the power) the 2nd goes to 0 (no x var so it goes to 0) repeat for y.
i'm confused :(
what goes to 0?
the y^2 goes to 0, because there is no x value there. so, by definition of derivatives it will go to 0 when u derive it. Easy mode for derivatives (when you just have polynomials) is to drop the power. so x -> 1 and any constant -> 0
hmmm... so what is i had something like U(x,y) = (x)(y) + x?
if i ***
d/dx (x*y+x) = y+1 d/dy (x*y+x) = x
oh man i dont know why im finding this hard.... dont you have to do the product rule or something? or am i thinking of it too complicating?
No need for product rule, Like Ishaan said, just think of one or the other (x,y) as a constant, or just some number, and do your derivatives... if it's any consolation, lots of people have trouble with this.
hmmm i think i get it now hahaha... but just to make sure, what if i had something like this then: 3x + xy... would i get this: MUx = 3 + y and MUy = x ????
yes! exactly :)
woohoo!!!! thanks for your help, i have an assignment due tomorrow and its 2:30 am and i was desperate to get help.... at least now i dont feel completely dumb haha
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