You are working in a chemistry lab. You have 1000 milliliters of pure acid. A dilution of acid is created by adding pure acid to water. A 40% dilution contains 40% acid and 60% water. You have been asked to make a 40% dilution and a 60% dilution of pure acid.
a.Write an equation in standard form that models the possible quantities of each dilution you can prepare using all 1000 milliliters of pure acid.
b.You prepare 700 milliliters of the 40% dilution how much of the 60% dilution can you prepare
c. How much water do you need to prepare 700 milliliters of the 40% dilution?

Question

anonymous · Answer

$$A)\ Dilution=\frac{V_a}{V_a+V_w}$$in percent, where V_a is equal to 1000(ml)
$$B)\ \ \ 0.4=\frac{V_a}{700}$$
$$V_a = 280$$
I have 1000-280 = 720 ml of acid left
$$0.6 = \frac{720}{720+V_w}$$
$$V_w = 480$$
I can prepare 720+480 = 1200 milliliters of the60% dilution
$$C)\ \ \ 0.4=\frac{V_a}{700} $$
$$V_a = 280$$
$$V_w = 700 - 280 = 420$$
I need 420ml of water to prepare the 700ml 40% dilution

anonymous · Answer

so thats the equation for part a

anonymous · Answer

It hass tobe in standard form

anonymous · Answer

$$Dilution(V_a + V_w)=V_a$$
$$Dilution*V_a + Dilution *V_w = V_a$$
Where Dilution is a positive rational.

anonymous · Answer

so does it change for all the other parts b and c

anonymous · Answer

Hmm... wait my answer isn't in standard form

anonymous · Answer

Ya

anonymous · Answer

Thats not in standard form Standard form is like this 2x+2y=200020202020

anonymous · Answer

thats just an example though

anonymous · Answer

I can write it as $$V_w+(1-\frac{1}{a})*V_a=0$$ which kinda matches the standard form$$Ax + By = C$$where A is 1, B is (1-1/a), and C is 0

anonymous · Answer

Just put it in standard form like right now Ax+By=c

anonymous · Answer

It is in standard form

anonymous · Answer

Just write it again in standard form.

anonymous · Answer

$$V_w + (1-\frac{1}{a})*V_a=0$$

anonymous · Answer

Are you sure.

anonymous · Answer

You may substitute x for V_w, and y for V_a$$x + (1-\frac{1}{a})y=)$$

anonymous · Answer

oops:$$x+(1-\frac{1}{a})y = 0$$

anonymous · Answer

Thanks ok i have one more question its at top can you help me with it its not as hard as this one