Question

2x^4 + 5x^3 + 3x^2 + 15x – 9 = 0

Find all roots and factor completely

Answer 1

2x^4 + 5x^3 + 3x^2 + 15x – 9 = 0
(x+3)(2x-1)(x^2+3)=0
x=1/2 or x=-3

Answer 2

can you explain how u factored pls

Answer 3

http://www.wolframalpha.com/input/?i=2x^4+%2B+5x^3+%2B+3x^2+%2B+15x+%E2%80%93+9+%3D+0+

Answer 4

we should get 4 roots right...?

Answer 5

two roots and then factored completely

Answer 6

angela the wolfram doesnt show steps can u help me out pls i need to know this for a test

Answer 7

yea
Wolfram says thr r two complex solutions too tht come from (x^2+3)=0

Answer 8

but how do you get (x^2 + 3)= 0

Answer 9

(x+3)(2x-1)(x^2+3)=0 is zero only whn (x+3)=0---> x=-3
or (2x-1)=0--->x=1/2
or x^2-3=0---> x^2=3--->x=+-sqr3

Answer 10

o ok thanks

Answer 11

welcome....(sorry for factorization) :/

Answer 12

no problem

Answer 13

(2x^4 +3x^2 -9) + (5x^3 + 15x) = 0
(x^2 + 3)(2x^2 + 3) + (5x)(x^2 + 3) = 0
(x^2 + 3)(2x^2 +3 + 5x) = 0
(x^2 +3)(x + 3)(2x - 1) = 0

x + 3 = 0
x = -3

2x - 1 = 0
x = 1/2