Question

help

Answer 1

#1

Answer 2

any and all advice is appreciated

Answer 3

should be the area of integration

Answer 4

http://tutorial.math.lamar.edu/Classes/CalcIII/DIPolarCoords.aspx
is what I'm learned this from. Convert\[x=r \cos \theta\]\[y=r \sin \theta\]
and \[dA=rdrd \theta\]

Answer 5

\[x^2+y^2=r^2(\cos^2 \theta +\sin^2 \theta)=r^2 \]
for the bounds it looks like theta varies from 0 to pi/2 and r varies from 0 to 2 so
\[\int\limits_{0}^{\pi/2}\int\limits_{0}^{2}r^2(rdrd \theta)=\int\limits_{0}^{\pi/2}\int\limits_{0}^{2}r^3drd \theta\]

Answer 6

\[=\int\limits_{0}^{\pi/2}2^4/4d \theta=\int\limits_{0}^{\pi/2}4d \theta=2 \pi\]

Answer 7

I'm not positive that's right though. You can try the link for yourself.

Answer 8

thank you thank you thank you!!

Answer 9

you're welcome!