Right. Now, it's not obvious how you did the integration, although it is helps a lot to remember that
1 + tan^2 x = sec^2 x.
So you need the integral of sec x
OpenStudy (anonymous):
right now i have the integral of (secx^2)^1/2
OpenStudy (jamesj):
Which is sec x
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OpenStudy (anonymous):
the integral of sec?
OpenStudy (jamesj):
\[\int\limits \sec x \ dx = \int\limits \frac{\sec x (\sec x + \tan x)}{\sec x + \tan x} \ dx\]
OpenStudy (anonymous):
but its secx^2 not just sec x
OpenStudy (jamesj):
No it's not. It is sec x, regardless of whatever notation cptnc used.
OpenStudy (anonymous):
The sqrt cancels the ^2 out
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