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Continuity question:
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Let f(x) = \begin{cases} m x - 16, &\text{if}\ x< -9\\ x^2+8 x - 7, &\text{if}\ x\geq -9 \end{cases} If f(x) is a function which is continuous everywhere, then we must have m=
To be continuous the functions must be equal at the switchover from one form to another, at the -9 value. So the two functions will be equal when x=-9, plug it in and find m.
Should it be like this: m(-9)-16=(-9)^2+8(-9)-7?
Yes, that is it. Well done!
So what is m?
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m= -2
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