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Mathematics 13 Online
OpenStudy (anonymous):

Continuity question:

OpenStudy (anonymous):

Let f(x) = \begin{cases} m x - 16, &\text{if}\ x< -9\\ x^2+8 x - 7, &\text{if}\ x\geq -9 \end{cases} If f(x) is a function which is continuous everywhere, then we must have m=

OpenStudy (anonymous):

To be continuous the functions must be equal at the switchover from one form to another, at the -9 value. So the two functions will be equal when x=-9, plug it in and find m.

OpenStudy (anonymous):

Should it be like this: m(-9)-16=(-9)^2+8(-9)-7?

OpenStudy (anonymous):

Yes, that is it. Well done!

OpenStudy (anonymous):

So what is m?

OpenStudy (anonymous):

m= -2

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