Question

A cyclist maintains a constant velocity of
4 m/s headed away from point A. At some
initial time, the cyclist is 253 m from point A.
What will be his displacement from his
starting position after 64 s?
Answer in units of m

What will be his position from point A after
that time?
Answer in units of m

Answer 1

whenever you see postion and velocity; you should know that the equations are related.

the derivative of position is velocity

Answer 2

v(t) = 4

p(t) = 4t + C ; at t=0, i believe it says we are -253 away

p(0) = 4(0) + C = -253
C = -253

p(t) = 4t -253

Answer 3

displacement tho is just distance away from starting point; in this case 4(64) = 256 m ... which is 3 m away from A

Answer 4

the equation stuff is just extra that wasnt needed :)

Answer 5

Thanks ALOT