Question

PLEASE help me work this problem. Preformed the indicated operations and simplify. Thanks: x-5/x-9-x+1/x+9+x-81/x²-81=

Answer 1

I'm assuming the problem is:

(x-5)/(x-9)-(x+1)/(x+9)+(x-81)/(x^2-81)

(x^2-81) can be factored into: (x-9)(x+9)

(x-5)/(x-9)-(x+1)/(x+9)+(x-81)/(x-9)(x+9) Find a common denominator:

(x-5)(x+9)/(x-9)(x+9)-(x+1)(x-9)/(x-9)(x+9)+(x-81)/(x-9)(x+9)

[x^2+4x-45-(x^2-8x-9)+(x-81)]/(x-9)(x+9)

(x^2+4x-45-x^2+8x+9+x-81)/(x-9)(x+9)

(13x-117)/(x-9)(x+9) (13x-117) can be factored into: 13(x-9)

[13(x-9)]/(x-9)(x+9) (x-9) cancels in both the numerator and denominator

13/(x+9) This is the answer