Question

8^(log(base2)x)-25^(log(base5)x)=4x-4

Answer 1

mmm that is good question.

Answer 2

(2^3) ^(log2 (x) ) - (5^2) ^(log5 (x))= 4x -4

Answer 3

2^(log2 (x^3) ) - 5^(log5 (x^2) ) = 4x-4

Answer 4

x^3-x^2-4x+4=0
x^2(x-1)-4(x-1)=0
(x-1)(x-2)(x+2)=0

so x=1,2,-2

Answer 5

but, check your answers in the eqn

Answer 6

you cannot take log of a negative.

So your answers are x=1,2

Answer 7

hopefully you follow the working out. Its just basic algebra

Answer 8

it works. thanx for the help

Answer 9

its just thinks like

a^(log a *(x) ) = x [ logorithms and indices are inverses]

(x^a)^b = x^(ab) and


n log (x) = log (x^n)

and seeing the patterns

Answer 10

It is one of the hardest high school questions I have seen on logs though.

Answer 11

your smart. thanks for helping me out. :)))