Suppose f(x) = Ax + B / (x^2) where A and B are constants. Find values of A and B so that y=2x+1 is tangent to y=f(x) when x= -1. When finding derivative use the definition of the derivative
: lim as h-0 ((f(x+h)-f(x))/h)

Question

Suppose f(x) = Ax + B / (x^2) where A and B are constants. Find values of A and B so that y=2x+1 is tangent to y=f(x) when x= -1. When finding derivative use the definition of the derivative 
: lim as h->0 ((f(x+h)-f(x))/h)

anonymous · Answer

$$y=2x+1......y'=\frac{2(x+h)+1-2x-1}{h}=\frac{2h}{h}=2$$ this is the slope of the tangent