Question

Algebraically explain the inverse of sin(x).

i.e. y=1/x and the inverse of this function is x=1/y.

Explain your reasoning.

Answer 1

I don't think this is possible, and I think this is a valid answer too.

Answer 2

be careful with it, because the sine function is many to one.

Answer 3

the inverse of sin(x) is expressed as sin^-1(x) or arcsin(x).

Answer 4

so if you take arcsin(sin(x))| -pi/2 <= x <= pi/2, you should get x

Answer 5

okay i see where the book is going with this I think

Answer 6

The explanation I think they want:
y=sin x and the inverse of this function is x=arcsin y
therefor inverse sine (or arcsin) is an operation that translates from a given y that is the sin of some x, back to the original x.

Answer 7

make a table of values for each equation. then graph
y=/x/+4