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If 4 coins are tossed what is the probability of at least 2 heads
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use binomial probability
= 4C2(0.5)^4 + 4C3(0.5)^4 + 4C4 (0.5)^4
or the complement; P0 and P1
I would map out all the possibilities: HHHH HHHT HHTH HTHH THHH HHTT HTHT HTTH TTHH THTH THHT HTTT THTT TTHT TTTH TTTT
Then you can count: 11/16
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