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Mathematics 19 Online
OpenStudy (anonymous):

If 4 coins are tossed what is the probability of at least 2 heads

OpenStudy (anonymous):

use binomial probability

OpenStudy (anonymous):

= 4C2(0.5)^4 + 4C3(0.5)^4 + 4C4 (0.5)^4

OpenStudy (amistre64):

or the complement; P0 and P1

OpenStudy (anonymous):

I would map out all the possibilities: HHHH HHHT HHTH HTHH THHH HHTT HTHT HTTH TTHH THTH THHT HTTT THTT TTHT TTTH TTTT

OpenStudy (anonymous):

Then you can count: 11/16

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