Question

Work of 2 Joules is done in stretching a spring from its natural length to 13 cm beyond its natural length. What is the force (in Newtons) that holds the spring stretched at the same distance (13 cm)?

Answer 1

The work needed to stretch a spring to this length is given by the equation W=Fd. If you store 2 J of energy in the spring, you have done 2J of work if you stretched the spring .13m (13 cm) the force required to do this is given by F=w/d or 2J/.13m in your case. Hope this helps.

Answer 2

Not quite physics dad. The work to stretch a spring is\[W=1/2*k*x^2\]where k is the spring constant. So first you'll want to use this equation to find the spring constant, then you can find the force from F=kx