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lim as x approaches 0 of (x^2)*(3+sin(x))/((x+sin(x))^2) I know I'm supposed to use the fact that lim as x approaches 0 of sin(x)/x = 1
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Divide top and bottom by x^2. Then I think you'll see it clearly.
ok I'll try that and see what happens
got it?
I've got (3+sin(x))/(x+sin(x)/x)^2 but I still can't see how to get the sin(x)/x out of it
your denominator isn't correct. check it again carefully
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isn't (x+sin(x)/x)^2 equal to (x+sin(x))^2/x^2
no ...
should I expand the (x+sin(x))^2?
\[\frac{1}{x^2} (x + \sin x)^2 = \left( x/x + \sin x / x \right)^2 = (1 + \sin x/x)^2\]
Oh! I distributed the \[1/x^2\] wrong
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Thanks a lot!
so what's the answer?
3/4 I think
Yes, that's right.
Thanks for helping me :)
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