Question

If you were to use the substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the second equation.

3x – 5y + z = 12
x + 6y – z = –4
2x – 5y – 2z = –8

4x + y = 8
–17y = 0
2x – 11y = 16
4x + 7y = –16
–23y + 4z = 24
–17y = 0
13y – 2z = 24
7y – 4z = 0

Answer 1

You have to get y by itself, i would recommend

Answer 2

how?

Answer 3

add 5y to both sides, getting 3x+z=12+5y. I usually just find the answer to the first equation and then see if it works in any of the others. From 3x+z=12+5y, you subtract 12 from both sides to get 3x+z-12=5y. Then, you divide both sides by 5, getting 3/5x+1/5z-12/5=y. Solve from there.

Answer 4

I know that the second system in x term would be
x=-4-6y+7

Answer 5

well these are the answer choices
4x + y = 8
–17y = 0

2x – 11y = 16
4x + 7y = –16

–23y + 4z = 24
–17y = 0

13y – 2z = 24
7y – 4z = 0

Answer 6

hmm

Answer 7

what are the top three equations

Answer 8

3x – 5y + z = 12
x + 6y – z = –4
2x – 5y – 2z = –8

Answer 9

i think I get it just give me a moment

Answer 10

my guess and this is a guess because i am not getting the exact answer would be the
-23y+4z=24 and -17y=0